Post by dougphresh on Apr 23, 2019 14:24:25 GMT -6
I'm trying to figure out a quick and simple way to figure out how much firepower different armaments have.
What I was thinking, was this - create a simple formula for the ratio of length to width of shell, a basic density, and then run a calculator to calculate a resulting total weight. Then it would be a simple matter of calculating that by number of mounts. If you're fancy I'm sure there's a way to factor in rate of fire.
I found an engineering calculator that does most of the work. It can calculate the weight of a cylinder of a given length, width and density.
www.matweb.com/tools/weightcalculator.aspx
What I would need is a good idea of the density of a ww1 era shell (Or the simplest way would be to calculate it as a simple cylinder of lead or steel) and the approximate length to width radio, that I would scale up with each caliber.
By way of example, I'm an artilleryman by trade and I've been up on 105s and 155s. I know that a 105mm shell is just over 30 lbs but a 155 despite being only 50mm bigger in diameter is about 100 lbs.
e: Would this be a good baseline?
Ammunition for the original low-angle guns introduced in World War I was Separate QF i.e. the shell and cartridge were separate items, but in World War II most guns used Fixed QF ammunition i.e. a single unit. The fixed Mk V ammunition was 44.3 inches (1.13 m) long and weighed 56 pounds (25 kg), while the projectile was 31 pounds
So in terms of the calculator to get that result:
Density: 1.5419 g/cc
Diameter: 4 in (duh!)
Length: 44.3 in
Weight: 31.0155 pounds (Pretty darn close!)
Using that Ratio of 44.30 : 4, the result of an 8 Inch Projectile Should be the Following:
Density: 1.5419 g/cc
Diameter: 8 in
Length: 88.60 in
Weight: 248.1244 pounds
Is that fairly close to the weight of an 8 inch projectile?
What I was thinking, was this - create a simple formula for the ratio of length to width of shell, a basic density, and then run a calculator to calculate a resulting total weight. Then it would be a simple matter of calculating that by number of mounts. If you're fancy I'm sure there's a way to factor in rate of fire.
I found an engineering calculator that does most of the work. It can calculate the weight of a cylinder of a given length, width and density.
www.matweb.com/tools/weightcalculator.aspx
What I would need is a good idea of the density of a ww1 era shell (Or the simplest way would be to calculate it as a simple cylinder of lead or steel) and the approximate length to width radio, that I would scale up with each caliber.
By way of example, I'm an artilleryman by trade and I've been up on 105s and 155s. I know that a 105mm shell is just over 30 lbs but a 155 despite being only 50mm bigger in diameter is about 100 lbs.
e: Would this be a good baseline?
Ammunition for the original low-angle guns introduced in World War I was Separate QF i.e. the shell and cartridge were separate items, but in World War II most guns used Fixed QF ammunition i.e. a single unit. The fixed Mk V ammunition was 44.3 inches (1.13 m) long and weighed 56 pounds (25 kg), while the projectile was 31 pounds
So in terms of the calculator to get that result:
Density: 1.5419 g/cc
Diameter: 4 in (duh!)
Length: 44.3 in
Weight: 31.0155 pounds (Pretty darn close!)
Using that Ratio of 44.30 : 4, the result of an 8 Inch Projectile Should be the Following:
Density: 1.5419 g/cc
Diameter: 8 in
Length: 88.60 in
Weight: 248.1244 pounds
Is that fairly close to the weight of an 8 inch projectile?